Hey Everyone!
First of all: I’m totally newbie, so please do not laugh heavily!
I just workin’ on my own self-taught learning project and have a little trouble.
I use a MYSQL DB wich has 2 table:
users and Locations (yes the second one is from the MapKit tutorial, thanks in this way for the tutorial ).
What is working fine?
- login,
- register,
- location insert to the Locations table
- location update,
- location delete
BUT:
I can’t solve that i wanted from this SQL:
SELECT * FROM Locations WHERE user_id=$user_id
I would like send user_id from the app to the service.php, and get back the datas in my tableView.
I don’t know how to hand-over the user_id from the app to the PHP and get the result in one function.
This is my code yet, and yes, there are not the hand-over method, coze’ i cant handle it…:
Xcode:
func downloadItems() {
let defaultValues = UserDefaults.standard
let user_id = defaultValues.string(forKey: "userid") //this is the active loggedin user_id
let urlPath = "http://myserverlocation.com/service.php"
let url: URL = URL(string: urlPath)!
let defaultSession = Foundation.URLSession(configuration: URLSessionConfiguration.default)
let task = defaultSession.dataTask(with: url) { (data, response, error) in
if error != nil {
print("Failed to download data")
}else {
print("Data downloaded")
self.parseJSON(data!)
}
}
task.resume()
}
PHP:
<?php
// Create connection
$con=mysqli_connect("localhost","user","pass","db");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$user_id = $_POST['user_id'];
$sql = "SELECT * FROM Locations WHERE user_id='$user_id'";
// Check if there are results
if ($result = mysqli_query($con, $sql))
{
// If so, then create a results array and a temporary one
// to hold the data
$resultArray = array();
$tempArray = array();
// Loop through each row in the result set
while($row = $result->fetch_object())
{
// Add each row into our results array
$tempArray = $row;
array_push($resultArray, $tempArray);
}
// Finally, encode the array to JSON and output the results
echo json_encode($resultArray);
}
// Close connections
mysqli_close($con);
?>
Thanks in advance for your help!
Joseph